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2 years ago

I NEED HELP ASAP!!! I'LL GIVE BRAINLIEST FOR THE CORRECT ANSWER!!!

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

6 0

Answer:

Step-by-step explanation:

am smert lad

FinnZ [79.3K]2 years ago

3 0

Answer:

y=2

x=3........//....

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Determine whether the underlined number is a statistic or a parameter. In a study of all 1963 employees at a college, it is foun

Ann [662]

Answer:

1. Parameter because the value is a numerical measurement describing a characteristic of a population

Step-by-step explanation:

A parameter is a fixed measure which describes the whole population while a statistic is a characteristic of a sample (which is a portion of the target population).

In a study of all 1963 employees at a college, it is found that "40%" own a computer.

The study involved the entire population of employees in the college, therefore the result describes the computer owning characteristics of the whole population under study. It is therefore a parameter.

The correct option is 1.

5 0

2 years ago

Which number, when raised to the power of 5, equals 2?

nevsk [136]

Answer:

1.148698

Step-by-step explanation:

6 0

2 years ago

4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

1 year ago

Read 2 more answers

Someone please help me with this!!

Paraphin [41]

PEMDAS tells us to use multiplication and division before addition and subtraction.

-5(8) ÷ 10 - 14 ÷ 7 - (-2)(3)

-40 ÷ 10 - 2 - -6

-4 - 2 + 6 two negatives make a positive so - - 6 = + 6

-6 +6

Answer: 0

3 0

2 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

Solution:

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

2 years ago