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mrs_skeptik [129]
3 years ago
15

The average time spent sleeping (in hours) for a group of medical residents at a hospital can be approximated by a normal distri

bution, with mean of 6.1 hours and standard deviation of 1.0 hour. Let x represents a random medical resedent selected at the hospital. Find P(x < 5.3).
Mathematics
1 answer:
nika2105 [10]3 years ago
8 0
First we calculate the z-score for this situation.
Z=\frac{X- \mu}{\sigma} = \frac{5.3-6.1}{1} = -0.8
Finding <em>P</em>(x < 5.3) is the same as finding <em>P</em>(<em>z</em> < -0.8).  Using a table of standard normal distribution and z-scores we see that the probability is 0.21186.
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