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kipiarov [429]
3 years ago
7

What is an expected outcome called

Mathematics
1 answer:
Triss [41]3 years ago
8 0
I think the answer is C. probability
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While sightseeing in Rome, Lance stopped to see the Colosseum. He learned that the height of the outer wall of the Colosseum mea
Tresset [83]

Answer:

157.44 feet

Step-by-step explanation:

Given that:

Lance is out for sightseeing in Rome.

Lance went to see the Colosseum.

Height of the outer wall of the Colosseum = 48 meters

Unit Conversion formula:

1 meter = 3.28 feet

To find:

Height of the outer wall of the Colosseum in feet.

Solution:

It is simple problem for the conversion of unit where we already know the value in one unit and the conversion formula as well.

We have to simply find how much 48 meters will be when converted in feet.

1 meter = 3.28 feet

48 meter = 48 \times 3.28 = <em>157.44 feet</em>

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3 years ago
Brown has own bakery he baked 5 cakes per day due to occasional christmas story to be in the whole christmas week how many cakes
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she would make 35 cakes
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3 years ago
What is the rate of change between (-3.7, 1.4) and (-3.5,1)?
Anarel [89]

Answer:

-2

Step-by-step explanation:

the rate of change or slope (M) is -2

Hope this helps:P

6 0
2 years ago
Given C=n+15, determine the value of C when n=4
puteri [66]

Answer: c=19 and n=4

please mark as brainliest  if it helped

6 0
3 years ago
Read 2 more answers
PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

5 0
2 years ago
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