Answer:x = - 5
y = 2
Step-by-step explanation:
The given system of simultaneous equations is expressed as
x + 3y = 1 - - - - - - - - - - - - - -1
4x + 4y = -12 - - - - - - - - - - - 2
We want to eliminate x. Multiplying equation 1 by 4 and equation 2 by 1, it becomes
4x + 12y = 4
4x + 4y = - 12
Subtracting the second equation from the first equation, it becomes
8y = 16
y = 16/8 = 2
Substituting y = 2 into equation 1, it becomes
x + 3 × 2 = 1
x + 6 = 1
x = 1 - 6 = - 5
Step-by-step explanation:
Edit:
a is 18
b is 36
c is 18
d is 18 times sqr root of 3
Answer:
1250 
Step-by-step explanation:
We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.
Let the length of the rectangle be 'X' feet and width be 'Y' feet.
As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.
As, X + 2Y = 100 → X = 100 - 2Y
Now, the area of the rectangle = XY = X × ( 100 - 2Y ).
i.e Area of the rectangle =
.
The general form of a quadratic equation is
.
The maximum value of a quadratic equation is given by
.
Therefore, the greatest value of
is at Y =
=
= 25.
Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.
Hence, the area of the rectangle is XY = 50 × 25 = 1250
.
Answer:
Local say "L" is going at a speed of 35mph...ok... and Express or "X" is going at 56mph.
by the time the two trains meet, and X is ready to overtake L, the distance that both have travelled, since is a parallel road, is the same, say "d". So if L has travelled "d" miles, then X had travelled "d" miles too, over the same road, maybe different lane.
now, because X left 1 1/2 hour later, by the time they meet, say X has been running for "t" hours, but because it left 1 1/2 hour later, L has been running for " t + 1 1/2 " hours, or " t + 3/2 " hours.
Step-by-step explanation:
so, they met 2 and a half hours later after X left, and a milllisecond later X overtook L.