Complete question is;
A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes.
a. What equation can you use to find the distance of the flowerbed from the hive?
b. How far is the flowerbed from the hive?
Answer:
A) (d/9) + 900 + (d/6) = 1080
B) d = 648 ft
Step-by-step explanation:
A) We are told that A bee flies at 9 feet per second directly to a flower bed from its hive.
Time taken is given as;
t = distance/speed
If distance is d from the hive to the flower bird.
Then, t1 = d/9
The bee stays at the flowerbed for 15 minutes. Thus, time spent at the flowerbird in seconds is; t2 = 15 × 60 = 900 seconds.
We are told that the bee flew directly back to the hive at 6 feet per second.
Thus,time is;
t3 = d/6
Since total time spent away from hive is 18 minutes, then converting to seconds, we have; t = 18 × 60 = 1080 s
Thus;
(d/9) + 900 + (d/6) = 1080
B) Since we have derived;
(d/9) + 900 + (d/6) = 1080
Then we can find d.
Multiply through by 18 to get;
2d + (900 × 18) + 3d = 1080 × 18
2d + 16200 + 3d = 19440
5d = 19440 - 16200
5d = 3240
d = 3240/5
d = 648 ft
-5x-1)