Answer:
Option A is the correct choice answer for the above question.
Explanation:
The programming concept says that every function returns some value. If the return value is not defined by the user then the function returns the garbage value otherwise it returns the defined value by the user.
The return value is defined by the user with the help of the "return" statement and with the help of the following syntax-
return value; // The return statement.
Hence the option A is right because it satisfies the above concept while the other is not because--
- Option B states that it must be longer than one line which is not correct.
- Option C states that it cannot be longer than one line but this line does not make any sense about the returned statement.
- Option D states that it describes the parameter value which is the wrong definition about the returned statement.
Answer:
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Answer:
The solution code is written in Java.
- public class Main {
- public static void main(String[] args) {
- System.out.print("Please enter a number: ");
- Scanner console = new Scanner(System.in);
- int n = console.nextInt();
- calculateSum1(n);
- calculateSum2(n);
- calculateSum3(n);
- calculateSum4(n);
- }
- public static void calculateSum1 (int num){
- int sum1 = 0;
- for(int i=1; i <= num; i++){
- sum1 += i*i*i;
- }
- System.out.println("Sum 1 : " + sum1);
- }
- public static void calculateSum2 (int num){
- int sum2 = num * num * (num + 1) * (num + 1) / 4;
- System.out.println("Sum 2 : " + sum2);
- }
- public static void calculateSum3 (int num){
- int sum3 = 0;
- for(int i=1; i <=num; i++){
- sum3 += i;
- }
- sum3 = sum3 * sum3;
- System.out.println("Sum 3 : " + sum3);
- }
- public static void calculateSum4 (int num){
- int sum4 = (num * (num + 1) * (2*num + 1)) / (4+2);
- System.out.println("Sum 4 : " + sum4);
- }
- }
Explanation:
Firstly we create four different methods that calculate the sum of the first n cubes in different ways (Line 13 - 43).
This is important to understand the concept of operator precedence to work out the different ways of summation.
For example, The operator * and / will always have higher precedence than +.
On another hand, any expression enclosed within the parenthesis will have highest precedence and therefore the value will be evaluated prior to others.
This is also important to understand the expression evaluation will always start from left to right.
