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daser333 [38]
2 years ago
7

"Write code that prints: Ready! countNum ... 2 1 Start! Your code should contain a for loop. Print a newline after each number a

nd after each line of text Ex: countNum = 3 outputs: Ready! 3 2 1 Start!"
Computers and Technology
1 answer:
BartSMP [9]2 years ago
6 0

Explanation:

#include <iostream.h>

#inlcude<conion.h>

void main()

{

  int count, x;

  clrscr();

  cout<<"Enter the count:";

  cin>> count;

  cout<<"Ready!\n";

  for(x=count;x>0;x--)

  {

     cout<<x<<"\n";

  }

  cout<<"Start";

  getche();

}

This is a simple program where the output is expected to be in reverse order. So we run a for loop starting from the count and decrements the counter by 1 every time when the loop runs and print the value. So to print the output in "new line" we include "\n".

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2 years ago
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In order to paint a wall that has a number of windows, we want to know its area. Each window has a size of 2 ft by 3 ft. Write a
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<h3>Writting the code:</h3>

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<em>public class WallArea {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner sc = new Scanner(System.in);</em>

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<em>        System.out.print("Wall height: ");</em>

<em>        double height = sc.nextDouble();</em>

<em>        System.out.print("Number of windows: ");</em>

<em>        double numberOfWindows = sc.nextDouble();</em>

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<em>    }</em>

<em>}</em>

See more about JAVA at brainly.com/question/12975450

#SPJ1

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