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Llana [10]
3 years ago
5

Sprinkle Inc. has outstanding 10,000 shares of $10 par value common stock. On July 1, 2020, Sprinkle reacquired 200 shares at $9

1 per share. On September 1, Sprinkle reissued 80 shares at $102 per share. On November 1, Sprinkle reissued 120 shares at $70 per share. Prepare Sprinkle's journal entries to record these transactions using the cost method.
Business
1 answer:
Ahat [919]3 years ago
6 0

Answer:

7/1/20

Dr Treasury Stock $18,200

Cr Cash $18,200

9/1/20

Dr Cash $8,160

Cr Treasury Stock $7,280

Cr Paid-in Capital - Treasury Stock $880

1/1/20

Dr Cash $8,400

Dr Paid-in Capital - Treasury Stock $2,520

Cr Treasury Stock

Explanation:

Preparation of Sprinkle's journal entries to record these transactions using the cost method.

7/1/20

Dr Treasury Stock $18,200

(200 shares * $91 per share)

Cr Cash $18,200

(Being To record the reacquired 200 shares)

9/1/20

Dr Cash $8,160

(80 shares * $102 per share)

Cr Treasury Stock $7,280

(80 shares * 91 per share)

Cr Paid-in Capital - Treasury Stock $880

($8,160-$7,280)

(Being To record the reissue of treasury stock)

1/1/20

Dr Cash $8,400

(120 shares * $70per share)

Dr Paid-in Capital - Treasury Stock $2,520

($91- $70 = $21* 120 shares)

Cr Treasury Stock

(120 shares * $91 per share) $10,920

(Being To record the reissue of treasury stock)

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3 years ago
At a growth (interest) rate of 8 percent annually, how long will it take for a sum to double? To triple? Use Appendix A for an a
Yanka [14]

Answer:

n =   ㏒ P ÷ ㏒ (1.08)

Explanation:

Compound interest rate

A = P × (1 + r)^{n}

where

P = principal amount (the initial amount you borrow or deposit)

r  = annual rate of interest (as a decimal)

A = amount of money accumulated after n years, including interest.

n  =  number of years

Since we want the principle amount to double i.e., A = 2P

put this in above equation

2P = P × (1 + r)^{n}

divide both sides by P, we get

P = (1 + r)^{n}

put r = 0.08

P = (1 + 0.08)^{n}

P = (1 .08)^{n}

Taking log on both sides

㏒ P =㏒ (1 .08)^{n}

㏒ P = n ㏒ (1.08)

n =   ㏒ P ÷ ㏒ (1.08)

8 0
3 years ago
A company has introduced a process improvement that reduces processing time for each unit, so that output is increased by 25% wt
Oksana_A [137]

Answer:

The productivity increase by 48.83%

Explanation:

old

60 units for 5 workers

5 x $12 = 60

material $16 x 60 = 960

overhead: 60 x 1.6 = 96

total revenue 60 x 31 =  1,860

total cosT: 60 + 960 + 96 = 1,116

productivity index_ 1,860 / 1,116 = 1,667

<em><u>now:</u></em>

output 60 + 25% = 75 units

6 workers x $12 = $72

materials $10 x 75 units = $750

overhead: $72 x 1.6 = $115.2

total revneue 75 units x $31 = 2,325

total cost: 75 + 750 + 115.2 = 940.2

productivity index_ 2,325 / 940.2 = 2,4728

percentage of improvement: ( it is calculate like a return on investment)

(2.4728 - 1.667) / 1.667 = 0.4883 = 48.83%

5 0
4 years ago
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