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KonstantinChe [14]
3 years ago
13

Tickets to a museum cost $16 each. For a field trip, the museum offers a $4 discount on each ticket. How much will tickets for 3

2 students cost?
Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

the tickets will cost 384 dollars in all

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What is the area of the trapezoid shown below?​
Olin [163]

Answer:

78 sqr units

Step-by-step explanation:

Use the Pythagorean Theorem to help find the base opposite the two.

The base of the second parallel line is sqrt(  (15^2) - (12^2)  ) = sqrt(81) = 9

The second base = 9 + 2 = 11

Area = (b1 + b2)*h/2

h = 12

b1 = 2

b2 = 11

h = 12

Area = (11 + 2)*12/2

Area = 13 * 12/2

Area = 78 square units

7 0
3 years ago
Read 2 more answers
Helppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
maks197457 [2]
What you must do in this case is to find the roots of the polynomial.
 We have then:
 x ^ 2 + 20x + 100 = 36
 Rewriting:
 x ^ 2 + 20x + 64 = 0
 The values of the roots are:
 x1 = -4
 x2 = -16
 Remember that the values of the roots are what make the polinome zero
 Answer:
 x1 = -4
 x2 = -16
3 0
3 years ago
What is the length of the arc on a circle with radius 21 in intercepted by a 25° angle? Round your answer to the nearest tenth.
Lana71 [14]

Answer:

Step-by-step explanation:

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ is the central angle formed at the center of the circle.

r represents the radius of the circle.

π represents a constant whose value is 3.14

From the information given,

r = 21 inches

θ = 25 degrees

Length of arc formed = 25/360 × 2 × 3.14 × 21 = 9.2 inches,

8 0
3 years ago
Read 2 more answers
Can someone please explain to me step by step how to solve this problem. <br><br> 4y-(3+y);y=2
avanturin [10]

Answer:

The answer is 3

Step-by-step explanation:

Plug in 2 for all the y variables and solve:

4(2)-(3+2)=

8-5=3

5 0
3 years ago
Read 2 more answers
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
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