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Naya [18.7K]
3 years ago
10

Please help due in 5 minutes !

Mathematics
2 answers:
Marizza181 [45]3 years ago
5 0

Answer:

x=0

The line of symmetry here is the same as the y-axis. Along the y-axis, x=0.

Doss [256]3 years ago
5 0

Answer:

I think your answer would be x=0, or A

Step-by-step explanation:

The line of symmetry is the y-axis, and the y-axis is always x=0.

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
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             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

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In the triangle QNP, the sides can be calculate as following:

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             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

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It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

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