Answer:
y + 4 = 2(x - 2)
Step-by-step explanation:
There is an infinite number of possible equation that satisfies this requirement. If the y = -4 when x = 2 in the equation, the point (2, -4) must be a solution to the equation. We can use the point-slope form to create an equation that satisfies this requirement. The point-slope form is:
y - y1 = m(x - x1) where m is the slope and (x1, y1) is a solution to the equation.
We know that (2, -4) must be a solution to the equation that we are trying to make. We can use (2, -4) as our (x1, y1). Since having (2, -4) as a solution is our only requirement, the slope can be any real number. I am going to make my slope 2 (you can choose whatever you want). So:
(x1, y1) = (2, -4)
m = 2
Now plug these into out point-slope equation:
y + 4 = 2(x - 2)
Remember, this is just one of infinitely many equations that meets the requirement.
Happy studying. :)
Answer:
-128
Step-by-step explanation:
y = -200-6(X) , x = -12
y = -200 - 6(-12)
y = -200 - (-72) (6x-12=-72) - with a - equals a +
y = -200 + 72
y = -128 ( you minus 200 and 72 and leave the minus sign)
The line drops 4 units between the points (1, 6) and (6, 2) as it goes over 5 units. Thus the point-slope form of the equation can be written as
... y - k = m(x - h) . . . . . . line with slope m through point (h, k)
... y - 6 = (-4/5)(x - 1)
Multiplying by 5 and subtracting the right side gives ...
... 5y - 30 = -4x +4
... 4x + 5y - 34 = 0 . . . . . equation in general form
Factors of 36 that add up to -12
-6 and -6
<span>(x − 6)(x − 6)
</span>
Set them both to equal 0 and solve for x
x - 6 = 0
x - 6 = 0
x = 6
x = 6
