The correct option is 20.
The score found for the sample is 20.
<h3>What is Standard error?</h3>
A standard error is a statistic that is applied to test the distribution of data. This metric is comparable to standard deviation. We can calculate the standard error if we know the sample size & standard deviation. It assesses the mean's precision.
Now, according to the question;
Sample mean; ![\bar{x}=40](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D40)
Sample variance; ![s^{2}=20](https://tex.z-dn.net/?f=s%5E%7B2%7D%3D20)
Thus, ![s=\sqrt{20}=4.47](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B20%7D%3D4.47)
Standard error SE = 1
The amount of scores with in sample must be determined here.
The standard error formula is as follows:
![S E=\frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=S%20E%3D%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
We might rearrange the formula as follows:
![\begin{aligned}\sqrt{n} &=\frac{s}{S E} \\n &=\left(\frac{s}{S E}\right)^{2}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Csqrt%7Bn%7D%20%26%3D%5Cfrac%7Bs%7D%7BS%20E%7D%20%5C%5Cn%20%26%3D%5Cleft%28%5Cfrac%7Bs%7D%7BS%20E%7D%5Cright%29%5E%7B2%7D%5Cend%7Baligned%7D)
Substituting the values;
![\begin{aligned}&n=\left(\frac{4.47}{1}\right)^{2} \\&n=19.98\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26n%3D%5Cleft%28%5Cfrac%7B4.47%7D%7B1%7D%5Cright%29%5E%7B2%7D%20%5C%5C%26n%3D19.98%5Cend%7Baligned%7D)
The sample's number of scores n = 19.98 = 20 (round up)
Therefore, the scores are in the sample is 20.
To know more about the Standard error, here
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Length = 6x - 12
Width = x
Area of a rectangle:
A = length x width
3744 = (x)(6x - 12)
3744 = 6x^2 - 12x
6x^2 - 12x - 3744 = 0
Use the quadratic equation to solve for x. The two solutions end up being 26 and -24. Since length is a scalar measurement, it can only be positive. Thus, the value of x is equal to 26 inches.
Width = 26 inches
Length = 6(26) - 12 = 144 inches
Hope this helps!! :)
Answer: the volume of a rectangular prisim with lenths (12ft , height 14 ft , and width 17 ft ) is
V=2856ft³
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Answer:
The probability that they will both be on time is 12/25.
Step-by-step explanation:
John is late 20% of the time.
So, he is prompt 80% of the time.
Ted is late 40% of the time.
So, he is prompt 60% of the time.
Since, both the events are independent,
p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)
× ![\frac{60}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7B100%7D)
= 0.80 × 0.60
= 0.48 or 48%
![=\frac{12}{25}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B12%7D%7B25%7D)
Hence, the probability that they will both be on time is 12/25.