Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.
The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!
Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.
y>x-2 -6> -4-2 -6= -6
That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.
y>2x+2
-6>(2)(-4) +2
-6> -8 +2
-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.
If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.
Answer:
71
Step-by-step explanation:
<u>refer</u><u> </u><u>the</u><u> attachment</u>
to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said
since
and it's given that FA and BA are 17 and 29 FB should be
therefore,
once again by two tangent theorem we acquire:
As BC=BH+CH,BC is
- 12+2.5

likewise,AD=AI+DI so,
- 21=17+DI [AD=21(given) and AI=17 (by the theorem)]
thus,
- DI=21-17=

By the theorem we obtain:
Similarly,DC=DG+CH therefore,
- DC=4+2.5=

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>
substitute what we have and got
simplify addition:
hence,
the Perimeter of ABCD is <u>7</u><u>1</u>
(b - 3x) + (-5b + 6x - 5)
= b - 3x - 5b + 6x - 5
= b - 5b - 3x + 6x - 5
= -4b + 3x - 5
E-Z View: 40 + 4.95x
View the best: 25 + 5.95x
Equal monthly bills:
40 + 4.95x = 25 + 5.95x
5.95x - 4.95x = 40 - 25
x = 15
Answer: 15