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Ber [7]
3 years ago
7

Write a rational equation that relates the desired percentage to the amount of % acid solution that needs to be added to liter o

f % acid solution to make a blend that is % acid, where < < . What is a reasonable restriction on the set of possible values of ? Explain your answer.
Mathematics
1 answer:
mart [117]3 years ago
8 0

This question is incomplete

Complete Question

Write a rational equation that relates the desired percentage p, to the amount A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid, where 0<p<100 . What is a reasonable restriction on the set of possible values of ? Explain your answer.

Answer:

100(0.1 + 0.3A)= (1 + A) P

Step-by-step explanation:

A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid,

Hence,

10% of 1 + 30% of A = p%(1 + A)

0.10 + 0.3A = (p/100)(1 + A)

Divide both sides by 1 + A

0.1 + 0.3A/ 1 + A = p/100

Cross Multiply

100(0.1 + 0.3A) = 1 + A(p)

From the above calculation, we can see that, the blend that would be formed is not lower than 10% or greater than 30%

10% < p< 30%

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Explanation:

Recall that y = f(x) since both are outputs of a function.

If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.

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EXPLANATION

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The expression given to us is,

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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


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{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


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