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Answer:
A. $6,400
B. $240
C. $1,000,000
D. $30,000
Explanation:
Requirement A, C, and D:
Prizes and awards are taxable income for a taxpayer. Any awards or prizes won from the lottery or television should be added to the income. Therefore, the Winning lottery is a taxable income for Kerry, $1,000,000. Again, Receiving the award for scientific research is also taxable income for Deborah, $30,000.
The winning award for accomplishments is also a taxable income. So, receiving a $6,400 worth gift bag is a taxable income for Cheline.
Requirement B:
There is an exception if the award is for tangible property and a long-years of accomplishment. At that time, the taxpayers will be excluded from some part of the necessary amounts to be paid as tax. If it is not a qualified award, the exclusion will be $400. If it is qualified, the tax exclusion is 1,600. Since Jon received a gold watch for 25 years of service and the gift is not qualified, he has to pay tax for $(660 - 400) = $240.
Answer:
$354,500
Explanation:
First find the amount invested ie the Present Value as follows :
n = 25 × 2 = 50
i = 5%
P/yr = 2
Pmt = $0
Fv = $500,000
Pv = ?
Using a Financial Calculator to enter the amounts as above, the Present Value is $145,471
Total Interest = Future Value - Present Value
= $500,000 - $145,471
= $354,529
Thus interest is $354,500 (nearest hundred dollars).
Answer:
The answer to this question is A
<span>n/2 = average number of items to search.
Or more precisely (n+1)/2
I could just assert that the answer is n/2, but instead I'll prove it. Since each item has the same probability of being searched for, I'll simulate performing n searches on a list of n items and then calculate the average length of the searches. So I'll have 1 search with a length of 1, another search looks at 2, next search is 3, and so forth and so on until I have the nth search looking at n items. The total number of items looked at for those n searches will be:
1 + 2 + 3 + 4 + ... + n
Now if you want to find the sum of numbers from 1 to n, the formula turns out to be n(n+1)/2
And of course, the average will be that sum divided by n. So we have (n(n+1)/2)/n = (n+1)/2 = n/2 + 1/2
Most people will ignore that constant figure of 1/2 and simply say that if you're doing a linear search of an unsorted list, on average, you'll have to look at half of the list.</span>
