All categories

3 years ago

Homework, confused on this 15 points

Mathematics

1 answer:

Zinaida [17]3 years ago

5 0

Answer:

Step-by-step explanation:

For the first question, you just need to think about what plus 1/2, or 2/4, equals 3/4. This would be D. or 1/4 because 1/4 + 2/4 = 3/4

For the second question, what number minus 4.4 gets you 13.2. This would have to be C. 17.6 since nothing else even makes sense

You might be interested in

What is 2 and 5/6 divided by 6 and 4/5

9966 [12]

Firstly I would revert these back to improper fractions:

So 17/6 ÷ 24/5

Then I would use keep, change, flip

So 17/6 * 5/24

Finally simplify

85/144

Final Answer: 85/144

3 0

3 years ago

Evaluate 32 + 12 = ( 6 – 3) x 8.

Brrunno [24]

Hello there!

(Equation #1) 32 + 12 = 44

(Equation #2) 6 - 3 = 3, 3 x 8 = 24

These both equations don't have the same answer, even though it says that they are equal with each other, if you could correct these these 2 equations I am willing to answer again.

Hope this helped!!

6 0

3 years ago

Read 2 more answers

#5 and #6 plz Will give Brainlyest!

Evgesh-ka [11]

Answer:

5. 3.93833333333 rounded: 3.94

6.Start with 1.8, then add 1.05 repeatedly or Start with 1.8, then add 1.05 repeatedly

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

2 years ago

The area of Ms. Anderson’s office floor measures 120

Maslowich

Answer:

72 square feet not covered

Step-by-step explanation:

100%-40% = 60%

60% of 120 = 0.6x120 = 72

8 0

3 years ago

Read 2 more answers