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sertanlavr [38]
3 years ago
12

Solve the following system of equations algebraically.

Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 12 , 15 )

Equation Form:  x = 12 , y = 15

Step-by-step explanation:

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What’s the answer to this?
Vanyuwa [196]

Answer:

answer c

Step-by-step explanation:

the two x-intercepts are (-4,0) and (2,0) so the factors of the equation are (x-2) and (x+4). if you multiply the factors it gives you the equation of the graph whic is x^2+2x-8 so c= -8 and b= 2

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3 years ago
WILL GIVE BRAINLIEST
gladu [14]

Answer:

The perimeter of triangle is 33 meters.

Step-by-step explanation:

Given that the triangle is Equivalent Triangle where all angles and sides are equal, so we can assume that:

7x - 17 = 4x - 5

7x - 4x = 17 - 5

3x = 12

x = 12 ÷ 3

x = 4

OR:

4x - 5 = 2x + 3

4x - 2x = 3 + 5

2x = 8

x = 8 ÷ 2

x = 4

Substitute x = 4 into all expressions:

7x - 17 = 7(4) - 17 = 11 meters

4x - 5 = 4(4) - 5 = 11 meters

2x + 3 = 2(4) + 3 = 11 meters

In order to find out the perimeters, you have to add up all the sides:

P = 11 + 11 + 11

P = 33 meters

3 0
3 years ago
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What is the standard form equation of 4x+7¥=11
yaroslaw [1]

This equation is in standard from unless you mean vertex standard form?  

5 0
3 years ago
Victor borrowed money at 5.25 percent simple annual interest. At the end of the year, the interest on the loan is $255.94. What
11Alexandr11 [23.1K]

Answer: 4,875.05

Step-by-step explanation:

I took the quiz

3 0
4 years ago
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The equation for the motion of an object with constant acceleration is d=vt+0.5at² where d is distance traveled in ft, v is star
sasho [114]

The expression for the distance the car travels after t seconds is d = 200t + 50t²

<h3>Equation of motion </h3>

From the question, we are to write an expression for the distance the car travels after t seconds

From the given information,

The equation for the motion of an object with constant acceleration is

d = vt + 0.5at²

For the race car,

v = 200 ft/s

a = 100 ft/s²

Putting the parameters into the equation, we get

d = 200t + 0.5(100)t²

d = 200t + 0.5 ×100)t²

d = 200t + 50t²

Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²

Learn more on Equations of motion here: brainly.com/question/20910641

#SPJ1

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