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Marta_Voda [28]
3 years ago
7

What is 3 divided by 1000 dived by 5

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0
0.0006 in the same way you put it 3/1000/5
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Mary can build 2 sand castles ( c ) in 4 hours ( t ). Write an equation in the form of c=rt that represents the relationship bet
wariber [46]
2 = r(4)
To find r, you've gotta divide it out.
2/4 = r/4
1/2 or 0.5 = r

c=(0.5)t
8 0
4 years ago
The graph of <img src="https://tex.z-dn.net/?f=y%20%3D%20ax%5E2%20%2B%20bx%20%2B%20c" id="TexFormula1" title="y = ax^2 + bx + c"
Reptile [31]

Answer:

(-b/2a, b^2/(4*a) - b^2/2a + c)

Step-by-step explanation:

For a general parabola:

y = a*x^2 + b*x + c

We can write the vertex as:

(h, k)

The x-value of the vertex is the value of the axis of symmetry.

Then we have:

h = x = -b/2a

Now we need to find the y-value of the vertex.

To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:

k = y = a*(-b/2a)^2 + b*(-b/2a) + c

k = b^2/(4*a) - b^2/2a + c

Then the coordinates of the vertex are:

(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)

8 0
3 years ago
Simplify 7.021 x 0.15 25pts
Helen [10]

Answer:

1.05315

Step-by-step explanation:

Simply multiply the two numbers to receive your answer

6 0
3 years ago
Read 2 more answers
What is the area of the real object that the scale drawing models?
Lynna [10]

Answer:

16 square cm

Step-by-step explanation:

2 * 8 (8 per one cm) is 16

5 0
3 years ago
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element X is a radioactive isotope such that every 21 years, its mass decreases by half. Given that the initial mass of a sample
pashok25 [27]

Answer:

The percentage rate of decay per year is of 3.25%.

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

Step-by-step explanation:

Equation for decay of substance:

The equation that models the amount of a decaying substance after t years is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Every 21 years, its mass decreases by half.

This means that A(21) = 0.5A(0). We use this to find r, the percentage rate of decay per year.

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{21}

(1-r)^{21} = 0.5

\sqrt[21]{(1-r)^{21}} = \sqrt[21]{0.5}

1 - r = 0.5^{\frac{1}{21}}

1 - r = 0.9675

r = 1 - 0.9675 = 0.0325

The percentage rate of decay per year is of 3.25%.

Given that the initial mass of a sample of Element X is 80 grams.

This means that A(0) = 80

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 80(1-0.0325)^t

A(t) = 80(0.9675)^t

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

8 0
3 years ago
Read 2 more answers
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