Part A:
Look at the image attached to my answer for the graph of the inequalities.
There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.
The green line is 2x+y≤8, the blue line is x+y≥4
Part B:
To test if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it doesn't satisfy one of them, then it isn't included in the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less then or equal to 8
Thus, (8, 10) cannot be a solution since the inequality is not true.
Part C:
I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.
The point (2, 3) means that Sarah can buy 2 cupcakes and 3 pieces of fudge to get at least 4 pastries for her siblings while staying within her 8 dollar budget.
Let me know if you need any clarifications. Happy Studying~

27mi/60min=9/20
9mi/20min=xmi/1min
Cross multiply
Divide by 20 on both sides
<span>x= 9/20
</span>
Answer: 10 4/5
Convert the mixed numbers to improper fractions
Use the algebraic formula for addition of fractions:
a/b + c/d = (ad + bc) / bd
Reduce fractions and simplify if possible
Step 5 is <u>Transitive property of equality</u> or <u>substitution</u>