All categories

3 years ago

I need the answers pls!!

Mathematics

2 answers:

vichka [17]3 years ago

7 0

First, a complementary angle are two angles that add up to 90. while supplementary add up to 180.

Complementary angles; 1 & 2, 3 & 4, 9 & 10, 11 & 12. (these all make one line which equals 180.)

Supplementary angles; 7 & 8, 5 & 7, 6 & 5, 8 & 6. (these all make up a 90 degree angle.)

Hope this helps. <3

Llana [10]3 years ago

5 0

complimentary angles equal 90 degrees so 1 and 2, 3 and 4, 9 and 10, 11 and 12 would be complimentary

supplementary angles equal 180 degrees so 6 and 5, 5 and 7, 7 and 8, and 8 and 6 would be supplementary

You might be interested in

Use the work shown below to write the equation for a line that passes through the points (−5, 0) and (−1, −8).

Dennis_Churaev [7]

Answer:

M = -2

b = -10

Step-by-step explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

m = (-8 -0)/(-1- -5)

= (-8-0)/(-1+5)

= -8/4

= -2

We now want to find the y intercept

y = mx+b is the slope intercept form of the equation

y = -2x+b

Using the point (-5,0)

0 = -2(-5) +b

0 = 10+b

Subtract 10 from each side

-10 = 10-10+b

-10 =b

The y intercept is -10

y= -2x-10

7 0

3 years ago

Read 2 more answers

If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r

Jobisdone [24]

The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58

6 0

3 years ago

Read 2 more answers

Simplify 5(x + 3) - 9x+4. O A. 14x+7 O B.-4x+19 O C. 14x+19 D. -4x+7

Julli [10]

Answer:

Step-by-step explanation:

distribute

5x+15-9x+4

combine like terms

-4x+19

8 0

3 years ago

Read 2 more answers

11th grade geometry:

Aliun [14]

Answer:

The perimeter is 72 units and the area is 149 square units.

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. (Rounded to the nearest unit)

The height of the triangle for the corresponding base $SB$ is 8.89 units.

Formula for the Area of triangle, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. (Rounded to the nearest unit)

3 0

3 years ago

A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m

Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

5 0

3 years ago