First, let's find the x and y intercepts
In the first equation
y - 4x = -1
Put x =0
y= - 1
(0, -1)
Put y=0 and the n solve for x
0 - 4x = -1
-4x = -1
x=0.25
(0.25 , 0)
The points for the first equation is (0, -1 ) and (0.25, 0)
Next is to find the intercts for the second equation
y + x = 4
put x=0
y = 4
(0, 4)
Put y =0
0 + x = 4
x = 4
( 4, 0)
The points for the second equation are;
(0, 4) and (4, 0)
Below is the graph
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+x=(-1)
Let x=0
y+x=(-1)
y+(0)=(-1)
y=(-1)
Let x=2
y+x=(-1)
y+(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
