Answer:
L = 100
W = 60
Step-by-step explanation:
2L + 2W = 320
-2L + 2W = -80
4W = 240
W = 60
L - W = 40
L - 60 = 40
L = 100
Barry will use the distance formula:
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
d = √[(4 - 3)² + (7 - 1)²]
d = 6.08 units
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
7.3 is your answer my guy