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liubo4ka [24]
3 years ago
11

Joe and Donna are in a pie eating contest. Donna eats 11 pies in 2.5

Mathematics
2 answers:
Anni [7]3 years ago
7 0
We’re is the picture
o-na [289]3 years ago
7 0
Donna will win because she eats 4.4 pies per minute and Joe eats 4 pies per minute.
Pie eaten by Donna: 11 pies / 2.5 minute = 4.4 pies per minute
Pie eaten by Joe: 10 pies / 2.5 minute = 4 pies per minute
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Multiply and Simplify<br> (x-5)(x^3 - 6x - 4)
Whitepunk [10]

Answer:

x4−5x3−6x2+26x+20

Step-by-step explanation:

(x−5)(x3−6x−4)

=(x+−5)(x3+−6x+−4)

=(x)(x3)+(x)(−6x)+(x)(−4)+(−5)(x3)+(−5)(−6x)+(−5)(−4)

=x4−6x2−4x−5x3+30x+20

=x4−5x3−6x2+26x+20

8 0
3 years ago
45 degreese is used in a pie chart to reperesent 6 people. How many people were there altogehter?
KatRina [158]
We can solve this problem by the rule of three.
A complete pie chart has 360º. 

45º----------------------6 people
360º--------------------    x

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Answer; 48 people. 
6 0
4 years ago
In the ASA Congruence Postulate, the side between the angles is called the ___ side.
rusak2 [61]
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6 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
mrs. lbare wrote three decimals on the bored follwed by the two blank spaces. Complete the sequence of numbers
andrew11 [14]
The rest of the sequence might be 10.5, 12.45, 14.10
5 0
4 years ago
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