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8090 [49]
4 years ago
10

WILL GIVE BRAINLIEST!! PLEASE HELP!!

Mathematics
1 answer:
lara31 [8.8K]4 years ago
5 0
We are given the functions y= x^{2} and y= -x^{2}.

let's consider some pairs in the graph of both functions.

 in y= x^{2}  we have (-2, 4), (2, 4), (3, 9), (-5, 25)

    in y=- x^{2}  we have (-2, -4), (2, -4), (3, -9), (-5, -25)


so for the same values of x, we have y's of equal value, but different sign.

This means that the functions are the reflections of each other with respect to the x-axis.

Answer: C <span>reflection over the x-axis</span>
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Answer:

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Step-by-step explanation:

Using law of projectile motion,

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Using the equation

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a = acceleration (taken as 9.8m/s )

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Plug in 188 / Vcos51 for time

0 = 0.5(-9.8)(188 / Vcos51)^2 + Vsin51 × (188 / Vcos51) + 0.9

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-233.1 = -4.9(188 / Vcos51)^2

47.57 = (188 / Vcos51)^2

Square root both sides

6.897 = 188 / Vcos51

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V = 43.31 m/s

The ball was hit with the speed of 43.31m/s

B)

Find the it takes the ball to travel 116m using

x = vt

116 = 43.31cos51 × t

t = 4.26s

Xf = 0.5at^2 + Vt + Xi

Xf = 0.5(-9.8)(4.26s)^2 + 43.31 sin51 (4.26s) + .9

= -88.92324 + 144.2838961764

Xf = 55.36m aprx 55m

the ball was 55m - 3m = 52m above the fence

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