<u>Given</u>:
The sum of 5 consecutive integers is 110.
Let the sequence be x, x + 1, x + 2, x + 3, x + 4
We need to determine the fourth number in the sequence.
<u>Value of x:</u>
Since, the sum of 5 consecutive integers is 110.
Thus, we have;
Adding the like terms, we have;
Thus, the value of x is 20.
<u>Fourth term:</u>
The fourth term of the sequence is x + 3
Substituting x = 20 in the term, we get;
Fourth term = 20 + 3 = 23
Thus, the fourth term of the sequence is 23.
Given:
The frequency distribution table.
To find:
The mean average score on a test.
Solution:
The frequency distribution table is
x a xa
y b yb
z c zc
Sum a+b+c xa+yb+zc
Now, the mean average score on the test is
Therefore, the mean average score on the test is 
.
Answer:
4
Step-by-step explanation:
subsitute the value of the variable into the expression and simplify.
Answer:
Step-by-step explanation:
The rate if increase of side of square is 7cm/s
dL/dt=7
At what area is the area increasing
dA/dt=?
Areas of square is give to be 36cm²
Analysis
Let L be the length of each side of the square, a square has equal side.
Area of square is give as L²
Area=L²
L²=36
i.e L=√36
L=6cm
Therefore at t=0 L=6cm and A=36cm²
A=L²
dA/dL=2L
Given that, dL/dt=7
Multiply the two differential together
dA/dt= dA/dL × dL/dt
dA/dt= 2L × 7
dA/dt= 2×6×7
dA/dt= 84cm²/s
The rate of increase of the square is 84cm²/s
That my friend is number 6
