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AnnZ [28]
3 years ago
13

How to do this question

Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0

9514 1404 393

Answer:

  AB = [[-6, -1][-4, 6][-15, 10]]

Step-by-step explanation:

Any of a number of on-line, spreadsheet, or calculator tools will find the matrix product for you.

The input and output of one such tool is shown below.

__

As you know, each term in the product matrix is the sum of products of a row in the left matrix and a column in the right matrix. The coordinates of that row and column are the coordinates of the result in the product matrix.

For example, row 2, column 1 of the product matrix is the sum of products ...

  (4)(-3) +(-2)(-4) = -12 +8 = -4 . . . . row 2, column 1 of the result

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A CIRCLE HAS A CIRCUMFENCE 43.96 YD FIND THE RADUIS OF THE CIRCLE
sleet_krkn [62]

Answer:

≈ 7

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=9%20%5Cdiv%202.43" id="TexFormula1" title="9 \div 2.43" alt="9 \div 2.43" align="absmiddle" cl
blsea [12.9K]
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3 0
3 years ago
Hello! Verify the identity. Please show your work! Use trigonometric identities to verify each expression is equal.
RSB [31]

Answer:

See Below.

Step-by-step explanation:

We want to verify the identity:

\displaystyle \csc^2 x -2\csc x \cot x +\cot ^2 x = \tan^2\left(\frac{x}{2}\right)

Note that the left-hand side is a perfect square trinomial pattern. Namely:

a^2-2ab+b^2=(a-b)^2

If we let <em>a</em> = csc(x) and <em>b</em> = cot(x), we can factor it as such:

\displaystyle (\csc x - \cot x)^2 = \tan^2\left(\frac{x}{2}\right)

Let csc(x) = 1 / sin(x) and cot(x) = cos(x) / sin(x):

\displaystyle \left(\frac{1}{\sin x}-\frac{\cos x }{\sin x}\right)^2=\tan^2\left(\frac{x}{2}\right)

Combine fractions:

\displaystyle \left(\frac{1-\cos x}{\sin x}\right)^2=\tan^2\left(\frac{x}{2}\right)

Square (but do not simplify yet):

\displaystyle \frac{(1-\cos x)^2}{\sin ^2x}=\tan^2\left(\frac{x}{2}\right)

Now, we can make a substitution. Let <em>u</em> = <em>x</em> / 2. So, <em>x</em> = 2<em>u</em>. Substitute:

\displaystyle \frac{(1-\cos 2u)^2}{\sin ^22u}=\tan^2u

Recall that cos(2u) = 1 - sin²(u). Hence:

\displaystyle \frac{(1-(1-2\sin^2u))^2}{\sin ^2 2u}=\tan^2u

Simplify:

\displaystyle \frac{4\sin^4 u}{\sin ^2 2u}=\tan^2 u

Recall that sin(2u) = 2sin(u)cos(u). Hence:

\displaystyle \frac{4\sin^4 u}{(2\sin u\cos u)^2}=\tan^2 u

Square:

\displaystyle \frac{4\sin^4 u}{4\sin^2 u\cos ^2u}=\tan^2 u

Cancel:

\displaystyle \frac{\sin ^2 u}{\cos ^2 u}=\tan ^2 u

Since sin(u) / cos(u) = tan(u):

\displaystyle \left(\frac{\sin u}{\cos u}\right)^2=\tan^2u=\tan^2u

We can substitute <em>u</em> back for <em>x</em> / 2:

\displaystyle \tan^2\left(\frac{x}{2}\right)= \tan^2\left(\frac{x}{2}\right)

Hence proven.

3 0
3 years ago
What is the value of the expression 8.3 × 104 − 2.5 × 103 − 1.9 × 104 written in scientific notation?
bezimeni [28]
Remark work with the two numbers that are 10^4 first. Then add in the one that goes to 10^3

Method one
You could change these all to integers and then take it back to scientific notation.

 83 000
<u>-19 000</u>
  64 000
<u>-   2 500
</u>  61 500 <u /><<<<<< answer

Method two
Keep the scientific notation.
 8.3 * 10^4
<u>-1.9 * 10^4</u>
 6.4 * 10^4
<u>-  .25*10^4</u>  Note the powers of ten must be the same.
  6.15*10^4 <<<<<<<< answer
<u>
</u>Either method works. 
<u>
</u>You could use your calculator to get the right answer. I'm not sure all calculators retain the scientific notation. Test yours to see what it does. Enter 8.3*10y^x 4 *1 = 
<u>
</u>Your calculator might have x^y or ^ to record powers. You may also have EE and one of your keys.
<u>
</u>See if your calculator returns 8.3*10^4 or if it returns 83000<u>
</u>
4 0
3 years ago
Read 2 more answers
Let f(x) = - 3x-1, h(x) = - X+3. Find (f o h)(-7)
gtnhenbr [62]

Answer:

f(x)= 20 h(x)= -4

Step-by-step explanation:

ive learnd this already :)

8 0
3 years ago
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