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arlik [135]
3 years ago
6

Quinton bought n number of shares for d dollars and paid a 1% commission. He sold the stock for y dollars and paid a flat fee of

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

y - (1.01nd + 7)

Step-by-step explanation:

Quinton bought n number of shares for d dollars and paid a 1% commission. It means he bought \dfrac{1}{100}nd=0.01nd

He sold the stock for y dollars and paid a flat fee of  $7. It means he sold y-7.

We need to find Quinton's net proceeds algebraically. It will be given as :

y-7-0.01nd\\\\=y-(0.01nd+7)

Hence, the correct option is (d) i.e. y - (1.01nd + 7)

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Solve for x in the triangle. Round your answer to the nearest tenth.
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Answer:

i think the answer might be 9

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What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
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The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

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A book had a length of 5 inches and a width of 8 inches. What is the perimeter of the book
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Read 2 more answers
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

7 0
3 years ago
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