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3 years ago

I need help on this question im testing

Mathematics

1 answer:

ycow [4]3 years ago

5 0

Answer:

500 cubic ft to gallons = 3740.26

Step-by-step explanation:

hope this helps :)

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What is the value of x in the equation x-2/3 + 1/6 =5/6

Taya2010 [7]

Answer:

x = 4/3.

Step-by-step explanation:

x-2/3 + 1/6 =5/6

Add 2/3 and subtract 1/6 from both sides:

x - 2/3 + 2/3 + 1/6 - 1/6 = 5/6 + 2/3 - 1/6

x = 5/6 + 2/3 - 1/6

x = 5/6 + 4/6 - 1/6

x = 8/6 = 4/3.

8 0

3 years ago

Read 2 more answers

Y= x^2+6x+4 axis of symmetry: vertex:

Juliette [100K]

Answer:

vertex (-3,-5) axis of symmetry x = -3

Step-by-step explanation:

4 0

3 years ago

A student found the solution below for the given inequality.

Pavel [41]

Correct option is A) The student is completely correct because the student correctly wrote and solved the compound inequality.

Step-by-step explanation:

Here we have , A student found the solution below for the given inequality.

1x-91<-4

x-9>4 and x-9 <-4

x> 13 and x<5

We need to find Which of the following explains whether the student is correct . Let's find :

We will be solving equation 1x-91<-4 or , $|x-9|$ . We know that for Modulus function , value inside modulus function is both positive & negative depending on particular value of x ! So ,

x-9 is positive :

Let's solve

⇒ $x-9$

⇒ $x-9+9$

⇒ $x$

x-9 is negative:

Let's solve

⇒ $-(x-9)$

⇒ $-(x-9)(-1)$

⇒ $x-9>4$

⇒ $x>13$

Therefore , Correct option is A) The student is completely correct because the student correctly wrote and solved the compound inequality.

3 0

4 years ago

Read 2 more answers

△ABC is a right triangle with right angle C. Side AC¯¯¯¯¯¯¯¯ is 6 units longer than side BC¯¯¯¯¯¯¯¯. If the hypotenuse has lengt

Vladimir [108]

Given:

In △ABC is a right angle triangle.

AC is 6 units longer than side BC.

$Hypotenuse=2\sqrt{17}$

To find:

The length of AC.

Solution:

Let the length of BC be x.

So, Length of AC = x+6

According to the Pythagoras theorem, in a right angle triangle

$Hypotenuse^2=Base^2+Perpendicualar^2$

△ABC is a right angle triangle and AC is hypotenuse, so

$(2\sqrt{17})^2=(x)^2+(x+6)^2$

$68=x^2+x^2+12x+36$ $[\because (a+b)^2=a^2+2ab+b^2]$

Subtract 68 from both sides.

$0=2x^2+12x+36-68$

$0=2x^2+12x-32$

$0=2(x^2+6x-16)$

Divide both sides by 2.

$x^2+6x-16=0$

Splitting the middle term, we get

$x^2+8x-2x-16=0$

$x(x+8)-2(x+8)=0$

$(x+8)(x-2)=0$

$x=-8,2$

Side cannot be negative, so x=2 only.

Now,

$AC=x+6$

$AC=2+6$

$AC=8$

Therefore, the length of AC is 8 units.

6 0

3 years ago

If 2/5 divided by blank = 4/5 what is blank

Helen [10]

2/5 ÷ x = 4/5
multiply both sides by x to get it out of the denominator.
2/5 = 4/5x
now divide each side by 4/5 to get x by itself.
2/5 ÷ 4/5 = x
divide fractions by multiplying the reciprocal of the divisor.
2/5x × 5/4 = x
10/20 = x
1/2 = x

So 2/5 divided by 1/2 =4/5

6 0

4 years ago