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damaskus [11]
2 years ago
6

What it means that [If x is a factor of p(x), what is the value of k?]

SAT
1 answer:
kompoz [17]2 years ago
7 0

Answer:

k = -4

Explanation:

Given

P(x) = (3x^2 - 5)(x + k) - 20

x is a factor

Required

Solve for k

x is a factor means that the polynomial can be divided successfully by x.

In other words, x is a zero of the polynomial.

i.e.

x = 0 and P(x) = 0

Substitute 0 for x in P(x)

P(x) = (3x^2 - 5)(x + k) - 20

P(x) = (3*0^2 - 5)(0 + k) - 20

P(x) = (0- 5)(k) - 20

P(x) = (-5)(k) - 20

P(x) = -5k - 20

Substitute 0 for P(x)

0 = -5k - 20

Collect Like Terms

5k = - 20

Divide both sides by 5

k = -4

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During last year's basketball season, Jackson attempted
OLga [1]

This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

150 free throws of which he made

120. So far this season, he's attempted 24 and made 16. A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted. Assuming calculations began with the start of last year's season, which of the following best approximates Jackson's overall free-throw percentage to date?

A. 67%

B. 73%

C. 78%

D. 80%

Answer:

B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

150 free throws of which he made

120

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

= 80%

This season, he's attempted 24 and made 16

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (16÷24) × 100

= 66.67%

Approximately = 67%

The best approximation for Jackson's overall free-throw percentage to date is

(Percent Free Throw for last season + Percent Free Throw for this season) ÷ 2

Percent Free Throw for last season

= 80%

Percent Free Throw for this season = 66.67%

Therefore, (80% + 66.67%) ÷ 2

= 146.67% ÷ 2

= 73.335%

Approximately = 73%

Therefore, Jackson's overall free-throw percentage to date is 73%

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