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3 years ago

Can anyone help me please? no links im finna cry

Mathematics

1 answer:

Zinaida [17]3 years ago

6 0

Answer:

k = 12

Step-by-step explanation:

(x^2 + 16x + 64) - (x^2 + 4x - 32)

distributing - 1

x^2 +16r + 64 - x^2 - 4x + 32

12x +96

take a factor of 12

12(x + 8)

K = 12

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Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

Rufina [12.5K]

Answer:

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)

3*(4k+4)=3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3)=5

3rd number: (2k+5)=7

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3 years ago

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5 0

3 years ago

Read 2 more answers

. If RST - UVW, find mZW. S 85 48° R TU W

Advocard [28]

Answer:

47°

Step-by-step explanation:

if it is the same, then the angles are the same

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4 0

3 years ago

Three tanks are capable of holding 361,841, and 901 of the greatest vessel winch can be used to fill each one of them on exact n

daser333 [38]

Answer:

Tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

Step-by-step explanation:

Three tanks are capable of holding $361,841,901$

To find which tank can be used to fill each one of them an exact number of time, find $HCF(361,841,901)$

$361=19^2\\841=29^2\\901=17(53)$

Therefore,

$HCF(361,841,901)=1$

So, tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

6 0

3 years ago

Confused on what do do first . Can anyone help ?

kirza4 [7]

So solve for q

first factor q out of the summation $q \sum^{\inf}_{k=2} (\frac{2}{3})^k=8$

now, determine what the summation is
$\sum^{\inf}_{k=2} (\frac{2}{3})^k =?$

its been a while since ive done summations so i dont remember any tricks but that summation is essentially equal to
$\frac{2}{3} ^2 +\frac{2}{3}^3+\frac{2}{3}^4+\frac{2}{3}^5+...$

or factored to be something like this
$\frac{2}{3}^2 *(1+\frac{2}{3}+\frac{2}{3}^2+\frac{2}{3}^3+...)$
which i believe there's a formula for

regardless using a calculator, the summation turns out to be 4/3 i think

you should definitely double check this step

so replacing the summation for 4/3, the equation is now
q*(4/3) =8

pretty easy to solve from here
divide 4/3 to both sides to get q

any questions?

5 0

3 years ago