Is y = 2(5)^x + 1 linear, exponential, or quadratic?
1 answer:
You might be interested in
I'm not sure what methods you've learned up to this point but one option is to apply separation of variables:
and then integrate from there,
exponentiate to isolate y,
Apply exponent rule,
rename this e^c as some new constant, perhaps A,
This A can only be positive, non-zero, but absorbing the plus/minus fixes that restriction,
Use your initial information to solve for this unknown value A,
solving for A, dividing by the exponential,
So we get a final result of
apply exponent rule again to get a better looking answer, and factor,
Lemme know if too confusing.