Answer:
2
Step-by-step explanation:
when it returns to the ground , h = 0
32t -16t2 = 0 and solve for t
t = 0, 2 ....0 is the start, 2 is when it returns
Look at the picture. I have no idea why I can't add an answer.
Answer:
I think E.
Step-by-step explanation:
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P