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Sonja [21]
3 years ago
6

The perimeter of a square is given as 8x+20. Write two different expressions for the perimeter. Use factoring to write one of th

e expressoins. Are the expressions equivalen? Explain
Mathematics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

P = 4(2x + 5)

P = (2x + 5)+(2x + 5)+(2x + 5)+(2x + 5)

Step-by-step explanation:

Given that:

Perimeter of square = 4 * s

Where s = side length

If perimeter, P = 8x + 20

Then,

4s = 8x + 20

Divide both sides by 4

4s / 4 = (8x + 20) / 4

s = 2x + 5

P = 4s

P = 4(2x + 5)

Or

P = 2x + 5 in 4 places

P = (2x + 5)+(2x + 5)+(2x + 5)+(2x + 5)

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For this case we have the following inequality:

6x-13

To find the solution we follow the steps below:

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6x-13

Adding 13 to both sides of the inequality we have:

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We subtract 6x on both sides of the inequality:

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Answer:

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3 years ago
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On a horizontal number line, –43 is located to the left of –35.
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Answer:

-43 <-35

Step-by-step explanation:

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3 years ago
A proportional relationship can be represented in the form of a
lidiya [134]

Answer:

a graph

Step-by-step explanation:

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2 years ago
At East Middle School, there are 585858 left-handed students and 609609609 right-handed students. The numbers of left- and right
lisabon 2012 [21]

Answer: C. Left-handed: 48 Right-handed: 504

E. Left-handed: 30 Right-handed: 315

Step-by-step explanation:

Here is the completed question:

At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed students at West Junior High are proportional to the numbers at East Middle School. Which of the following could be the numbers of left-handed and right-handed students at West Junior High?

A. Left-handed: 42 Right-handed: 483

B. Left-handed: 28 Right-handed: 378

C. Left-handed: 48 Right-handed: 504

D. Left-handed: 56 Right-handed: 560

E. Left-handed: 30 Right-handed: 315

Since it's direct proportion, we have to calculate the constant of proportionality which will simply be:

= 609 / 58 = 10.5

A. Left-handed: 42 Right-handed: 483

Constant = 483/42 = 11.5

Incorrect

B. Left-handed: 28 Right-handed: 378

Constant = 378/28 = 13.5

Incorrect

C. Left-handed: 48 Right-handed: 504

Constant = 504/48 = 10.5

Correct

D. Left-handed: 56 Right-handed: 560

Constant = 560/56 = 10

Incorrect

E. Left-handed: 30 Right-handed: 315

Constant = 315/30 = 10.5

Correct

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3 0
3 years ago
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A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 85
insens350 [35]
First, "boxes of two sizes" means we can assign variables:   Let x = number of large boxes        y = number of small boxes   "There are 115 boxes in all"    means    x + y = 115      [eq1] Now, the pounds for each kind of box is:     (pounds per box)*(number of boxes) So,   pounds for large boxes     +    pounds for small boxes      =    4125 pounds                  "the truck is carrying a total of 4125 pounds in boxes"          (50)*(x)                   +              (25)*(y)                  = 4125    [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2.  Let's solve for x:    x = 115 - y          [from eq1]      50(115-y) + 25y = 4125             [from eq2]      5750 - 50y  + 25y = 4125           [distribute]      5750 - 25y = 4125       -25y = -1625          y = 65             [divide both sides by (-25)]   There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x:   x = 115 - y   x = 115 - 65   x = 50    There are 50 large boxes.
3 0
3 years ago
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