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4 years ago

What is 6x-13<6(x-2)

Mathematics

2 answers:

ohaa [14]4 years ago

8 0

For this case we have the following inequality:

$6x-13$

To find the solution we follow the steps below:

We apply distributive property on the right side of inequality:

$6x-13$

Adding 13 to both sides of the inequality we have:

$6x$

We subtract 6x on both sides of the inequality:

$0$

Thus, we have that any value of "x" makes the inequality fulfilled. Thus, the solution is given by all real numbers.

Answer:

The solution set is (-∞,∞)

Cloud [144]4 years ago

3 0

Answer:

(-infinity, infinity)

Step-by-step explanation:

6x-13<6(x-2)

6x-13<6x-12

6x-6x<-12+13

0<1

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Many us employess received a 3% raise in 2012 suppose an employee made 47,000 in 2011 and received a 3% raise. What did she make

WITCHER [35]

First lets get 3% into decimal form.

3% is 3/100 = 0.03

Now multiply 0.03 by 47000 to get how much extra money she was going to get.

47000 * 0.03 = 1410

Now we just add
47000 + 1410 = 48410 is what she was going to make in 2012

Another way to do this is

(47000)(1+0.03) = 48410

you would use (1+0.03) which tells you she increased in pay.

4 0

3 years ago

Using Distributive Property, what is the simplified answer to (6+9v)6 ?

inna [77]

36+54v

Multiply 6 with both 6 and 9v

4 0

3 years ago

Read 2 more answers

in the unted states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches. If 16

yaroslaw [1]

Answer:

Probability that their mean height is less than 68 inches is 0.0764.

Step-by-step explanation:

We are given that in the united states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches.

Also, 16 men are randomly selected.

Let $\bar X$ = sample mean height

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height = 69 inches

$\sigma$ = population standard deviation = 2.8 inches

n = sample of men = 16

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the mean height of 16 randomly selected men is less than 68 inches is given by = P( $\bar X$ < 68 inches)

P( $\bar X$ < 68 inches) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{68-69}{\frac{2.8}{\sqrt{16} } }$ ) = P(Z < -1.43) = 1 - P(Z $\leq$ 1.43)

= 1 - 0.9236 = 0.0764

Now, in the z table the P(Z x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.43 in the z table which has an area of 0.92364.

Therefore, probability that their mean height is less than 68 inches is 0.0764.

3 0

4 years ago

Write the square roots of 49 i in ascending order of the angle.

Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

$r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}} = \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )$