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dolphi86 [110]
3 years ago
12

Please show working ​

Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

234 cm²

Step-by-step explanation:

area = (base*height) / 2 = (52*9) / 2 = 234

You might be interested in
What algebraic expression represents GK?
dsp73

Answer:

Part a) GK=(7x+1)

Part b) GH=5 units and JK=8 units

Step-by-step explanation:

Part a) what algebraic expression represents GK?

we know that

GK=GH+HJ+JK

step 1

Find GH

we have

GH=GJ-HJ

substitute the given values

GH=(2x+3)-x=x+3

step 2

Find JK

JK=HK-HJ

substitute the given values

JK=(6x-2)-x=5x-2

step 3

Find GK

GK=GH+HJ+JK

we have

GH=x+3

HJ=x

JK=5x-2

substitute

GK=(x+3)+x+(5x-2)

GK=(7x+1)

Part b) If GK=15, what are GH and JK?

we know that

GK=(7x+1)

For GK=15

substitute the value of GK and solve for x

15=(7x+1)

7x=15-1

7x=14

x=2

<u><em>Find the value of GH</em></u>

GH=x+3

substitute the value of x

GH=2+3=5 units

<u><em>Find the value of JK</em></u>

JK=5x-2

substitute the value of x

JK=5(2)-2=8 units

7 0
3 years ago
28 ft2 at $3.89 per square foot $71.98 $111.44 $108.92 $106.40
Alinara [238K]
The answer would be $108.92. You can solve this by multiplying @* by 3.89, getting 108.92.
4 0
3 years ago
PLEASE HELP
Masja [62]

Answer:

y = 50x + 20

Step-by-step explanation:

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }

Use the slope-intercept formula to find the slope.

m = \frac{120 - 20}{2 - 0}

m = \frac{100}{2} = 50

The y-intercept is where the line crosses the y-axis.

3 0
3 years ago
Read 2 more answers
Slove and I will give you a best anwser thing
olga2289 [7]

Answer:

Below:

Step-by-step explanation:

When finding the power of a power, simplify the expression by <em><u>multiplying</u></em> the exponents

a^{m^n} =m^m^n

12^4^-5 = 12^{4*-5=12^-20=\frac{1}{12^{20}}

(-3)^{72}

6 0
3 years ago
Consider the equation below. (If you need to use -[infinity] or [infinity], enter -INFINITY or INFINITY.)f(x) = 2x3 + 3x2 − 180x
soldier1979 [14.2K]

Answer:

(a) The function is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) The local minimum is x = 5 and the maximum is x = -6

(c) The inflection point is x = -\frac{1}{2}

(d) The function is concave upward on \left(- \frac{1}{2}, \infty\right) and concave downward on \left(-\infty, - \frac{1}{2}\right)

Step-by-step explanation:

(a) To find the intervals where f(x) = 2x^3 + 3x^2 -180x is increasing or decreasing you must:

1. Differentiate the function

\frac{d}{dx}f(x) =\frac{d}{dx}(2x^3 + 3x^2 -180x) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f'(x)=\frac{d}{dx}\left(2x^3\right)+\frac{d}{dx}\left(3x^2\right)-\frac{d}{dx}\left(180x\right)\\\\f'(x) =6x^2+6x-180

2. Now we want to find the intervals where f'(x) is positive or negative. This is done using critical points, which are the points where f'(x) is either 0 or undefined.

f'(x) =6x^2+6x-180 =0\\\\6x^2+6x-180 = 6\left(x-5\right)\left(x+6\right)=0\\\\x=5,\:x=-6

These points divide the number line into three intervals:

(-\infty,-6), (-6,5), and (5, \infty)

Evaluate f'(x) at each interval to see if it's positive or negative on that interval.

\left\begin{array}{cccc}Interval&x-value&f'(x)&Verdict\\(-\infty,-6)&-7&72&Increasing\\(-6,5)&0&-180&Decreasing\\(5, \infty)&6&72&Increasing\end{array}\right

Therefore f(x) is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) Now that we know the intervals where f(x) increases or decreases, we can find its extremum points. An extremum point would be a point where f(x) is defined and f'(x) changes signs.

We know that:

  • f(x) increases before x = -6, decreases after it, and is defined at x = -6. So f(x) has a relative maximum point at x = -6.
  • f(x) decreases before x = 5, increases after it, and is defined at x = 5. So f(x) has a relative minimum point at x = 5.

(c)-(d) An Inflection Point is where a curve changes from Concave upward to Concave downward (or vice versa).

Concave upward is when the slope increases and concave downward is when the slope decreases.

To find the inflection points of f(x), we need to use the f''(x)

f''(x)=\frac{d}{dx}\left(6x^2+6x-180\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f''(x)=\frac{d}{dx}\left(6x^2\right)+\frac{d}{dx}\left(6x\right)-\frac{d}{dx}\left(180\right)\\\\f''(x) =12x+6

We set f''(x) = 0

f''(x) =12x+6 =0\\\\x=-\frac{1}{2}

Analyzing concavity, we get

\left\begin{array}{cccc}Interval&x-value&f''(x)\\(-\infty,-1/2)&-2&-18\\(-1/2,\infty)&0&6\\\end{array}\right

The function is concave upward on (-1/2,\infty) because the f''(x) > 0 and concave downward on (-\infty,-1/2) because the f''(x) < 0.

f(x) is concave down before x = -\frac{1}{2}, concave up after it. So f(x) has an inflection point at x = -\frac{1}{2}.

7 0
3 years ago
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