I dont know what benchmark means but <em />I hope this works<em>. </em>First, multiply 7 10ths by the denominator of 12. 7/10 *12= 84/120.
Then multiply 5 12ths by 10. 5/12 *10=50/120. So, 7/10 > 5/12
Answer:24 or 4
Step-by-step explanation:
2x2=4 4x6=24 24 or 4
Answer:
mean= 4.68
variance= 1.0296
Step-by-step explanation:
mean= n×p
n=6
p=0.78
mean= 6×(0.78)
= 4.68
variance= n×p×(1-p)
= 6 × 0.78×(1-0.78)
= 1.0296
When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)
Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:
• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]
• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]
• bisecting an arbitrary interval
gives the intervals
and ![\left[\frac{a+b}2,b\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Ba%2Bb%7D2%2Cb%5Cright%5D)
(1) See below for a diagram. Basically, the distance on the ground from the person to the building (34 ft) is adjacent to the angle of elevation (74 degrees) and the height of the building (labeled h in the diagram) is the side opposite the angle. Since we are dealing with opposite and adjacent we use the tangent of the angle and tan = opp/adj
Specifically,


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feet.
Please be sure your calculator is set to degrees (not radians) when you do this problem.
(2) Here since P & Q are complimentary it means that their sum is 90 degrees. Since this is a right triangle that means that the remaining angle (R) must be the right angle. See below for a diagram.
sin = opp/hyp. As the sin Q = 9/41 this means that 9 is the length of the side opposite Q (the side PR) and 41 is the length of the hypotenuse. This makes the remaining side (QR) 40 in length.
cos = adj/hyp. If we focus on angle P the side adjacent (next to) is 9 and the hypotenuse is 41. Thus the cos of P = 9/41.
You could have also realized that if P & Q are complimentary the sin P = cos Q and the cos P = sin Q. We were not asked about tangent but it is also the case that tan P = cot Q and cot P = tan Q.