Can someone answer these pls
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144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length
Force F=10 lb
From the hookes Law
Therefore, calculate k for the spring for
Work done in stretching a spring through a length dx is
For calculating the work done for stretching the spring to x=6in=(6/12)feet beyond the natural length, Integrate over the limits of x=0 to x=1/2
Therefore,
That is,
The answer that is given is for stretching the spring to 4 inches.
Mass of 10 m of chain length is 80kg. This implies, Mass per unit meter length of the chain is
Consider a small length dx of the chain at the end point A. Work done in lifting the small length dx over the height of x meters is
Now, integrate over the the value of x from
x=0 when end of the chain A is on the ground
x=6 when end of the chain A reaches 6 m above the ground
That is,
Hence,144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length
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