An alternative under consideration involves incurring $50 in costs to generate $60 in revenue. The differential revenue for this
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Answer:
maximum height reached = 35 feet
and
Step-by-step explanation:
writing linear motion equations
where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.
given u = 48 ft/s, and a = acceleration due to gravity g = -9.8
1 m = 3.28 feet therefore g becomes -9.8×3.28
here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.
therefore f(t) becomes
to find max height we should find differentiation of f(t) and equate it to 0
therefore we get 48 = 32.144t
t = 1.49 s
therefore max height f(1.49) = 71.67-36.67 = 35 feet