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LenKa [72]
2 years ago
6

Find the area of a square that has a side that measures 5 mm.

Mathematics
2 answers:
Fed [463]2 years ago
5 0

Answer:

Step-by-step explanation:

LENGTH OF SQUARE = 5 MM

so now

The area of square

= (5 mm)²

= 25 mm²

Oksanka [162]2 years ago
4 0

Answer:

25 mm^2

Step-by-step explanation:

Because the sides of a square are all equal, that means the length = 5 and the width = 5.

To find the area, you do length * width so for this square it would be 5 * 5 = 25.

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Is the base (leght width) plus the areas of each of the four triangular faces
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Please help no du mb answers
vladimir1956 [14]

Answer:

A = (-2,5)

B = (5,5)

the distance between the points is 7

Step-by-step explanation:

6 0
3 years ago
In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma
bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a)=\frac{v-u}{t}

a=\frac{60\times 60\times 60}{4}

a=54\times 10^3 mi/h^2

To reach a speed of 183.58mi/h with an acceleration of 54\times 10^3 mi/h^2

Using equation of motion

v=u+at

183.58=0+(54\times 10^3)t

t=\frac{183.58}{54\times 10^3}

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

s=ut+\frac{1}{2}at^2

5=0+\frac{1}{2}\times 54\times 10^3 \times t^2

t=0.01360 hour

or t=48.98\approx 49 s

7 0
3 years ago
The Versatech Corporation has decided to produce three new products. Five branch plants now have excess production capacity. The
RSB [31]

Answer: provided in the explanation segment

Step-by-step explanation:

here i will give a step by step analysis of the question;

A: Optimization Formulation

given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5

Objective function: Minimize manufacturing cost (Z)

Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33

s.t

X11 + X12 + X13 + X14 + X15 = 600

X21 + X22 + X23 + X24 + X25 = 1000

X31 + X32 + X33 = 800

X11 + X21 + X31 <= 400

X12 + X22 + X32 <= 600

X13 + X23 + X33 <= 400

X14 + X24 ​​​​​​ <= 600

X15 + X25 <= 1000

Xij >= 0 for all i,j

B:

Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.

cheers i hope this helps!!

3 0
3 years ago
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