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2 years ago

PLEASE SOLVE I WILL MARK BRAINLIEST HURRY PLEASE

Mathematics

1 answer:

suter [353]2 years ago

3 0

Applying the Pythagorean theorem, the missing lengths in the right triangles are:

1. √19 ≈ 4.4

2. √96 ≈ 9.8

3. √60 ≈ 7.7

4. √231 ≈ 15.2

5. √21 ≈ 4.6

6. √24 ≈ 4.9

<h3>What is the Pythagorean Theorem?</h3>

The Pythagorean theorem is a formula that can be used to find the leg of a right triangle, and is given as: c² = a² + b², where a and b are the smaller legs and c is the longest leg/hypotenuse.

1. missing leg = √(10² - 9²) = √19 ≈ 4.4

2. missing leg = √(11² - 5²) = √96 ≈ 9.8

3. missing leg = √(8² - 2²) = √60 ≈ 7.7

4. missing leg = √(16² - 5²) = √231 ≈ 15.2

5. missing leg = √(5² - 2²) = √21 ≈ 4.6

6. missing leg = √(7² - 5²) = √24 ≈ 4.9

Learn more about the Pythagorean theorem on:

brainly.com/question/343682

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Find the midpoint of points A(8,-7) and B(3,-1) graphically

sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

$M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

$M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

$M(\frac{8+3 }{2}, \frac{-7 +-1}{2} )$

$M(\frac{8+3 }{2}, \frac{-7 -1}{2} )$

$M(\frac{11 }{2}, \frac{-8}{2} )$

$M(5.5, -4 )$

Midpoint = (5.5, -4)

Hope this helps!

3 0

2 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: