SOLUTION:
PQR is a right-angle triangle.
Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.
Pythagoras theorem is as displayed below:
a^2 + b^2 = c^2
Where c = hypotenuse of right-angle triangle
Where a and b = other two sides of right-angle triangle
Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.
c = PQ = 16cm
a = PR = 8cm
b = QR = ?
a^2 + b^2 = c^2
( 8 )^2 + b^2 = ( 16 )^2
64 + b^2 = 256
b^2 = 256 - 64
b^2 = 192
b = square root of ( 192 )
b = 13.8564...
b = 13.86 ( to 2 decimal places )
FINAL ANSWER:
Therefore, the length of QR is 13.86 centimetres to 2 decimal places.
Hope this helps! :)
Have a lovely day! <3
Hello,
Sandy is right .
Other method:
V=168=(10+4)*3*4
Answer:
Step-by-step explanation:
Let (x,y) be midpoint of P(3,4) & Q(5,−2)
Midpoint formula for two points (a,b) and (c,d) is
(x,y) =(
2
a+c
,
2
b+d
).
x=
2
3+5
=4
y=
2
4−2
=1
∴ (x,y)=(4,1)
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
