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3 years ago

Suppose M is the midpoint of FG. Find the missing measure. FM=12x−4, MG=5x+10

Mathematics

2 answers:

Paha777 [63]3 years ago

6 0

Answer:

$\overline{FM}=20$

$\overline{MG}=20$

Therefore,

$\overline{FG}=40$

Step-by-step explanation:

Once M is the midpoint of FG, we conclude that

FM is half of FG and MG is half of FC and hence, FM = MG.

Given:

$\overline{FM}=12x-4$

$\overline{MG}=5x+10$

$\overline{FM} = \overline{MG} \implies 12x-4 = 5x+10 \implies 7x=14 \implies \boxed{x = 2}$

So,

$\overline{FM}=12x-4 = 12(2)-4=24-4=20$

$\overline{MG}=5x+10 = 5(2)+10 = 10+10 =20$

Dmitrij [34]3 years ago

5 0

Answer:

FG = 17x - 6

Step-by-step explanation:

FG = 12x + 5x + 10 - 4

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» Round 13.045 to the nearest whole number.

pentagon [3]

Answer:

Step-by-step explanation:

Have a good day

7 0

2 years ago

Read 2 more answers

George earns 9% commission on all of his sales. He had sales of 89,400 for the month. Paris works for a different company, and a

Sholpan [36]

Answer: 10.53%

Step-by-step explanation:

George £89400 @ 9% = £8046 so income = £89400+£8046=£97446

Harris (Paris?) gets £447 more so 97446+447=£97893

and this represents sales of £89400 plus commission

so Harris' commission = £97893-£89400 = £8493

So last stage is what commission percentage is £8493 of original sales £89400 = 10.53%

8 0

3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

3 years ago

2. Use the following picture for this question:

Art [367]

Answer:

a. $24\sqrt{3}$ and 41.6

b. 52.1

Step-by-step explanation:

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

Note: the exact value of tan 60 is $\sqrt{3}$

Thus, we can write $Tan(60)=\frac{y}{24}\\y=24*Tan(60)\\y=24*\sqrt{3} \\y=24\sqrt{3}$

Approximate value (rounded to nearest tenth): $24\sqrt{3} =41.6$

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

$Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1$

4 0

3 years ago

11 PTS! 5 STARS! THANKS ON PROFILE AND QUESTION1 FIRST TO ANSWER ALL 5 GETS BRAINLIEST!

denis-greek [22]

1) Answer: 21
As y varies directly with x, this means that the ratio y/x is always a constant.
In other words, the equation can be written as y = kx, where k is a constant term.

Thus, $-\frac{14}{4} = -\frac{y}{6}$
y = 21

2) Answer: C
Exactly the same process as above.
Here's another method:
25 = k(140)
k = 25/140 = 5/28

Thus, when y = 36, 36 = kx
36 = 5/28(x)
36 * 28/5 = x; x = 201.6

3) 9 = k(12)
9/12 = k and k = 3/4

4) On the graph, it hits y = 1 at x = 4.
Thus, we can rewrite the equation as:
y = (1/4)x, where the constant term is 1/4

5) y = kx
The distance represents the x-ordinates, and the time represents the y-ordinates.

9.5/475 = 0.02
4 = 0.02(x), in hours.
x = 200 miles.

4 0

3 years ago