Answer:it's A
Explanation:I just got it wrong cuz of the other person maybe I should just study
Answer:
Written in Python
rgb = []
colr = []
for i in range(0,3):
inp = int(input("Input: "))
if (inp >=0 and inp<=255):
rgb.append(inp)
else:
print("Range is 0 to 255")
exit()
colr.extend(rgb)
rgb.sort()
for i in range(0,3):
print(colr[i] - rgb[0])
Explanation:
The next two lines declares two empty lists
rgb = []
colr = []
The following iteration lets user input into rgb list
<em>for i in range(0,3):</em>
<em> inp = int(input("Input: "))</em>
<em> if (inp >=0 and inp<=255):
</em>
<em> rgb.append(inp)
</em>
<em> else:
</em>
<em> print("Range is 0 to 255")
</em>
<em> exit()</em>
This line copies the content of rgb to colr
colr.extend(rgb)
This line sorts list rgb
rgb.sort()
This iteration calculates and prints the difference between each individual input and the smallest of the inputs
<em>for i in range(0,3):</em>
<em> print(colr[i] - rgb[0])</em>
Answer:
The number of bits allocated to information transmission should be 1216.
Explanation:
Efficiency is given as
Efficiency=Bits of Information/Total Bits
where
Bits of Information is x which is to be calculated
Total Bits is given as TB which is the sum of Bits of Information and the additional bits.
The additional bits above are the sum of Flags, Address , Control and CRC bits which are all given in the question and add up to 16+8+8+32=64 bits.
So Total Bits is given as TB which is 64+x
The efficiency is given as 95% or 0.95 so the equation becomes
So the number of bits allocated to information transmission should be 1216.
The logic gates are shown right below your truth tables... lol.
A program to demonstrate doubly linked list using pointers – insert (beginning, end, middle), delete(beginning, end, middle),view) is:
/* Initialize nodes */
struct node *head;
struct node *one = NULL;
struct node *two = NULL;
struct node *three = NULL;
/* Allocate memory */
one = malloc(sizeof(struct node));
two = malloc(sizeof(struct node));
three = malloc(sizeof(struct node));
/* Assign data values */
one->data = 1;
two->data = 2;
three->data = 3;
/* Connect nodes */
one->next = two;
one->prev = NULL;
two->next = three;
two->prev = one;
three->next = NULL;
three->prev = two;
/* Save address of first node in head */
head = one;
<h3>What is a Doubly Linked List?</h3>
This refers to the linked data structure that contains of a set of sequentially linked records called nodes.
The requested program is given above.
Read more about doubly linked list here:
brainly.com/question/13326183
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