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3 years ago

How do you find the mean?

Mathematics

1 answer:

Elina [12.6K]3 years ago

3 0

Answer:

mean is when you add all the numbers together then divide by how many values there are

Step-by-step explanation:

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A group of friends wants to go to the amusement

Zepler [3.9K]

Answer:

The maximum amount of people that can go to the amusement park is 15.

Step-by-step explanation:

First you create an equation to represent the question

8.75+25.75x≤420

You put the less than or equal to sign because 420 is the maximum amount of money.

Now you just solve the equation.

25.75x≤420-8.75

25.75x≤411.25

x≤411.25/25.75

x≤15.9708738

Then you have to round down because you cant have .9 of a person.

So x≤15

Then, Check your solution

8.75+(25.75 x 15)≤420

8.75+386.25≤420

395≤420

That is true. But to make sure that is the maximum add another 25.75

395+25.75≤420

420.75≤420

This is equation is false so, our answer is correct.

The maximum amount of people that can go to the amusement park is 15.

5 0

2 years ago

Find the equation for the line that passes through (-1, -2) and (4, 3). Is the

Leto [7]

Answer:

The answer to your question is a) y = x - 1 b) the point is not on the line

Step-by-step explanation:

Data

A ( -1, -2)

B (4, 3)

C ( 3, 1)

Process

1.- Find the slope of the line (m)

Formula

m = $\frac{y2 - y1}{x2 - x1}$

Substitution

m = $\frac{3 + 2}{4 + 1} = \frac{5}{5} = 1$

2.- Find the equation of the line

Formula

y - y1 = m(x - x1)

Substitution

y + 2 = 1(x + 1)

Solve for y

y = x + 1 - 2

y = x - 1

- Prove that the point (3, 1) is on the line

1 = 3 - 1

1 = 2

The point is not on the line because 1 ≠ 2

5 0

4 years ago

The probability is 0.4 that a traffic fatality involves an intoxicated or alcohol-impaired driver or nonoccupant. In 7 traffic

Luden [163]

Answer:

$P(X=3)=0.2903\\\\P(X \geq 3)=0.5801\\\\P(X\leq 3)0.7102$

$P(2\leq x\leq 4 )=0.7451$

c. mean=2.8

d . standard deviation=1.2961

Step-by-step explanation:

We determine that the accident rates follow a binomial distribution. The rate of success p=0.4 and sample n=7:

$P(x)={n\choose x}p^x(1-p)^{n-x}$

#the probability of exactly three;

$P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X=3)={7\choose 3}0.4^3(0.6)^{4}\\\\=0.2903$

#At least(more than 2)

$P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X\leq 2)\\\\=1-{7\choose 0}0.4^0(0.6)^{7}-{7\choose 1}0.4^1(0.6)^{6}-{7\choose 2}0.4^2(0.6)^{5}\\\\=1-0.0280-0.1306-0.2613\\\\=0.5801$

#At most 3;

$P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X \leq 3)={7\choose 0}0.4^0(0.6)^{7}+{7\choose 1}0.4^1(0.6)^{6}+{7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}\\\\\\\=0.0280+0.1306+0.2613+0.2903\\\\=0.7102$

b. Between 2 and 4:

Using the binomial expression, this probability is calculated as:

$P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(2\leq x\leq 4 )={7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}+{7\choose 4}0.4^4(0.6)^{3}\\\\\\\\\=0.2613+0.2903+0.1935\\\\=0.7451$