Answer:
i think c
Step-by-step explanation:
Answer:
a) The probability that a box containing 3 defectives will be shipped is ![51.74\%](https://tex.z-dn.net/?f=51.74%5C%25)
b) The probability that a box containing only 1 defective will be sent back for screening is ![17.39\%](https://tex.z-dn.net/?f=17.39%5C%25)
Step-by-step explanation:
Hi
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 20 items of the box (discounting the 3 defectives) as the possible ways to succeed, so
Finally we need to compute
, therefore the probability that a box containing 3 defectives will be shipped is
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 22 items of the box (discounting the defective 1) as the possible ways to succeed, so
Then we need to compute
, therefore the probability that a box containing 1 defective will be shipped is
Finally the probability that a box containing only 1 defective will be sent back for screening will be ![P(BS)=1-P(S)=1-0.8260=0.1739=17.39\%](https://tex.z-dn.net/?f=P%28BS%29%3D1-P%28S%29%3D1-0.8260%3D0.1739%3D17.39%5C%25)
Answer:
1.75
Step-by-step explanation:
used a calculator
Answer:
YES
Step-by-step explanation:
Answer:
option (B) I'm certain of.
but if you are required to choose more than one then option (B) and (C) since polynomials are coefficients with power 2.
Step-by-step explanation:
Hope this helps.
Good luck.