GIVING BRAINLIEST FOR ANSWER AND STEPS:
1 answer:
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Answer:
see below
Step-by-step explanation:
exponent to log: = c ---> logₐc = b
ie. question 6
log ₁₀(3x+1) = 2 ----->
that will get you through questions 1 to 3, 5 to 6, and 8
in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3
for questions 7 and 9,
remember that:
logₐc + logₐd = logₐ(cd)
logₐc - logₐd = logₐ()
remember change of base is , this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e
1-
number 2) is correct
2- 3) is true
11) Jacob is not correct. because 6radical 5 is irrational
12) radical 20 is an irrational number but
so a+b is irrational
but
so b+c is rational
good luck
number 2) is correct
2- 3) is true
11) Jacob is not correct. because 6radical 5 is irrational
12) radical 20 is an irrational number but
so a+b is irrational
but
so b+c is rational
good luck
Answer:
When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.
Step-by-step explanation:
- The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.
- Calculate the volume to the nearest whole number.
- Use the given values and calculate the proportionality constant as well as required solution.
Step 1 of 2
Write the inversely proportionality relation between the volume and pressure of a gas in container.
Where volume is represented by v and pressure is represented by p.
Remove the proportionality and place a constant say k.
Substitute the given values of nitrogen that v=29.5 and
p=2000 and calculate the value of k from above equation.
Step 2 of 2
Substitute the value p=14.7 and above calculated k value in the equation