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liubo4ka [24]
3 years ago
15

True or false to graph data points together you need to use a coordinate plane

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0

Answer by Mimiwhatsup: True. Without a coordinate plane there is no way to graph them together at least not in a way that is correct.

Source: "We can use coordinate planes to represent points, two-dimensional geometric figures." (CK12)

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Breanna wrote a number that is 4 units from 0 on the number line.
Hatshy [7]
The two answers are -4 and 4, because 0-4 is -4 and 0+4 is 4. Hope this helps
5 0
3 years ago
Evaluate the expression -4x+5y-14 when x=0 and y= 3/5​
emmainna [20.7K]

Answer:

-11

Step-by-step explanation:

Plug in 0 for x and 3/5 for y into the expression

-4(0) + 5(3/5) - 14

Multiply the numbers inside the parentheses

0 + 3 - 14

3 - 14 = -11, which is your answer

5 0
3 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
Tom used twenty gallons of water to
oksano4ka [1.4K]

Answer:

y=20x + 40x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help fast! This is polynomials help
antiseptic1488 [7]

Answer:

  • incorrect
  • correct
  • incorrect

Step-by-step explanation:

A + B = (-4x^2 +2x -5) +(3x^2 +6) = x^2(-4+3) +x(2) +(-5+6) = -x^2 +2x +1

  The given sum is Incorrect.

__

A - C = (-4x^2 +2x -5) -(-5x -4) = -4x^2 +x(2+5) +(-5+4) = -4x^2 +7x -1

   The given difference is Correct.

__

B + C = (3x^2 +6) +(-5x -4) = 3x^2 -6x +2

  The given sum is Incorrect.

5 0
3 years ago
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