If the 2q is raised to the second power the answer is 2q^2+7q+3
That’s really nice man. I’m sure she’ll love it
B..............
c>=3 and n<0 and p<=(9-3 c)/n
Well, the keyword here is One of the performers insist on being the last.
So, the amount of performers that we can arrange freely is 7 performers.
Different ways we can schedule their appearance is :
7 ! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5040
hope this helps
First you need to pick a number for y. Lets say you pick 0
Then you need to +3 to each side
Then you can say 3=x+2 or -3=x+2.
To find x you need to subtract 2.
You answer would be (1,3) and (-5.-3)
