If the coefficient of x^2 is negative, the graph will be n shaped and curve down instead of like a u shape if it was positive. If the vertex is below the x axis and curves down, it won’t pass the x axis, Tia is right.
Answer: x=-3/2
Step-by-step explanation:
Answer:
i think b
Step-by-step explanation:
tell me if im wrong
X^-n = 1/x^n
Your fraction becomes:
1/ {(m^5 t^2)(27m^6t^3)} now combine the powers in the denominator
1/ (27 m^11 t^5)
