All categories

2 years ago

8.) cos D A B C D 6 8

Mathematics

1 answer:

vagabundo [1.1K]2 years ago

6 0

Using Pythagorean theorem, we can find that DG is 10.(I don't think I need to explain this)

Now cosD means the adjacent side over the hypotenuse.

The side adjacent to <D is 6 and the hypotenuse is 10 so

cosD=6/10=3/5

Which means the correct answer is choice D.

Hope this helped!

You might be interested in

Solve for S 12s = 72

ryzh [129]

Answer:

s=6

Step-by-step explanation:

72/12=6 simplify both sides

3 0

2 years ago

Read 2 more answers

The sets of numbers 7,24,25 and 9,40,41 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain or

ololo11 [35]

Answer:

Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

7-24-25

7² + 24² = 25²

49 + 576 = 625

625 = 625

9-40-41

9² + 40² = 41²

81 + 1600 = 1681

1681 = 1681

8 0

2 years ago

Read 2 more answers

1 121 12321 1234321.......56th

Rudik [331]

Answer:

Bro it is too hard to find . Hope you understand me

3 0

2 years ago

Simplify the following fractions by putting them in lowest terms or by performing the indicated operations.

AleksAgata [21]

The answer is 9(3+x)
My work is in the attached image

3 0

2 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

2 years ago