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AlladinOne [14]
2 years ago
13

The question is in the attachment. Please answer

Mathematics
2 answers:
maria [59]2 years ago
4 0
The guy on top is correct
Temka [501]2 years ago
4 0

Answer:

74°

Step-by-step explanation:

LMN is a central angle so LMN = LN

LN = 74°

LMN = 74°

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I need help as soon as possible someone please help
Zigmanuir [339]

Answer:

 b

Step-by-step explanation:

6 0
3 years ago
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The baker uses 3/4 cups of sugar for each cake. If the baker makes 2 cakes per week
GrogVix [38]

Answer:

6 cups of sugar

Step-by-step explanation:

3/4x2=1.5

1.5x4=6

6 0
3 years ago
What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)? (1 point) y = −2x + 1 y = −2x − 1 y
Stolb23 [73]

Answer: y=2x+1

Step-by-step explanation:

The slope of the line is \frac{7-3}{3-1}=\frac{4}{2}=2

Using the point (1,3) to substitute into point-slope form,

y-3=2(x-1)\\\\y-3=2x-2\\\\\boxed{y-2x+1}

3 0
1 year ago
There are 35 men and 25 women on a bus. If 20 married couples leave the bus, the number of men is how many times the number of w
Angelina_Jolie [31]

Answer:

3

Step-by-step explanation:

15 men would be left

5 women would be left

6 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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