Which is the equation of the given line?

Mathematics

1 answer:

myrzilka [38]3 years ago

3 0

Answer:

x=2

Step-by-step explanation:

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A rock climber starts at an elevation 630 feet above sea level and descends to a point 180 feet lower than his starting point. W

Mila [183]

Answer:

A. 450 feet

Step-by-step explanation:

If the rock climber starts at 630 feet above sea level, decending down 180 feet lower than his starting point (630) would put him at 450 feet above sea level. Hope this helps

7 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ,0)left parenthesis, plus min

lora16 [44]

Answer:

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the relation between the focus and semi major axes and semi minor axes as:

$\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 } \\ \\ \mathbf{c^2 = 49 } \\ \\ \mathbf{c = \sqrt{49 }}$